Problem 34 Find the sample size required to... [FREE SOLUTION] (2024)

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Chapter 7: Problem 34

Find the sample size required to estimate the population mean. Data Set 1 "Body Data" in Appendix B includes pulse rates of 147 randomlyselected adult females, and those pulse rates vary from a low of 36 bpm to ahigh of 104 bpm. Find the minimum sample size required to estimate the meanpulse rate of adult females. Assume that we want \(99 \%\) confidence that thesample mean is within 2 bpm of the population mean. a. Find the sample size using the range rule of thumb to estimate \(\sigma .\) b. Assume that \(\sigma=12.5\) bpm, based on the value of \(s=12.5\) bpm for thesample of 147 female pulse rates. c. Compare the results from parts (a) and (b). Which result is likely to bebetter?

Short Answer

Expert verified

Sample sizes are 479 (range rule) and 260 (\( \sigma = 12.5 \)). The latter is probably better.

Step by step solution

01

Determine the Required Formula

The formula for calculating the sample size required to estimate the population mean with a given level of confidence and margin of error is \[ n = \left( \frac{Z_{\frac{\alpha}{2}} \cdot \sigma}{E} \right)^2 \] where \( Z_{\frac{\alpha}{2}} \) represents the critical value from the standard normal distribution, \( \sigma \) is the population standard deviation, and \( E \) is the margin of error.

02

Identify Given Values and Compute Critical Value for 99% Confidence

Given: Confidence level, \( 99\% \), leads to \( \alpha = 0.01 \), thus \( \frac{\alpha}{2} = 0.005 \).From the Z-table, the critical value \( Z_{0.005} \) is 2.576.The margin of error \( E \) is 2 bpm.For part (a): Use the range rule of thumb to estimate \( \sigma \) as \( \frac{\text{Range}}{4} = \frac{104 - 36}{4} = 17 \). For part (b): Given \( \sigma = 12.5 \) bpm.

03

Calculate Sample Size Using the Estimated \( \sigma \)

Using the formula: \[ n = \left( \frac{2.576 \cdot 17}{2} \right)^2 = \left( 21.892 \right)^2 \approx 479 \] Therefore, the sample size required using the estimated \( \sigma \) is 479.

04

Calculate Sample Size Using the Given \( \sigma = 12.5 \)

Using the same formula: \[ n = \left( \frac{2.576 \cdot 12.5}{2} \right)^2 = \left( 16.1 \right)^2 \approx 260 \] Therefore, the sample size required using \( \sigma = 12.5 \) is 260.

05

Compare the Results

The sample sizes calculated are 479 (using the range rule of thumb) and 260 (using \( \sigma = 12.5 \) bpm). Part (b) uses an actual standard deviation from the data, so is likely a better estimate and requires a smaller sample size.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

population mean

The population mean is the average value of a characteristic in a whole population. For example, in our exercise, we want to estimate the mean pulse rate of all adult females. This mean is often denoted by the Greek letter \( \mu \), and it represents the central value around which all individual measurements tend to cluster.

To calculate this population mean exactly, we would need to measure the pulse rate of every single adult female, which is obviously impractical. Instead, we take a sample (a subset of the population) and use the sample mean to estimate the population mean. The larger and more representative the sample, the more accurate our estimate of \( \mu \) will be.

In many real-world applications, such as our body data example, we rely on statistical methods like confidence intervals and the central limit theorem to make educated guesses about the population mean based on our sample data.

confidence interval

A confidence interval provides a range of values within which we can be certain the population mean lies, to a specified level of confidence. In our exercise, we are looking for a 99% confidence interval. This means that we are 99% sure that the true mean pulse rate falls within our calculated range.

The formula for a confidence interval around the population mean is given by: \[ \mu = \bar{x} \pm Z_{\frac{\alpha}{2}} \frac{\sigma}{\sqrt{n}} \] where \( \bar{x} \) is the sample mean, \( Z_{\frac{\alpha}{2}} \) is the z-value corresponding to our desired level of confidence, \( \sigma \) is the population standard deviation, and \( n \) is the sample size.

For a 99% confidence level, the critical z-value (\( Z_{\frac{\alpha}{2}} \)) is 2.576. This z-value provides the number of standard deviations we would expect the interval to cover. By calculating the margin of error \( E \) and applying it to our sample mean, we produce the confidence interval for the population mean.

standard deviation

The standard deviation (\( \sigma \) or s for a sample) is a measure of how spread out the values in a data set are. It shows the average distance of each data point from the mean of the data set. In the context of our pulse rate data, the standard deviation gives us an idea of how much the pulse rates of different individuals vary from the average pulse rate.

To find the sample size required to estimate the population mean, we need an estimate of the standard deviation. In our exercise, we use two methods to get this estimate:

  • The range rule of thumb, which approximates standard deviation as one-fourth of the range of the data
  • An actual standard deviation measured directly from the data (12.5 bpm in this case)

The formula for calculating standard deviation (\( s \)) for a sample is \[ s = \sqrt{ \frac{ \sum (x_i - \bar{x})^2 }{ n - 1 } } \] where \( x_i \) represents each value in the sample, \( \bar{x} \) is the sample mean, and \( n \) is the sample size.

Knowing the standard deviation is crucial because it affects the width of our confidence intervals and the required sample size. A smaller standard deviation generally means a smaller required sample size, as seen when comparing the results of parts (a) and (b) in our exercise.

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Problem 34 Find the sample size required to... [FREE SOLUTION] (3)

Most popular questions from this chapter

Use the data and confidence level to construct a confidence interval estimateof \(p,\) then address the given question. A random sample of 860 births in New York State included 426 boys. Construct a\(95 \%\) confidence interval estimate of the proportion of boys in all births.It is believed that among all births, the proportion of boys is \(0.512 .\) Dothese sample results provide strong evidence against that belief?Use the relatively small number of given bootstrap samples to construct theconfidence interval. In a Consumer Reports Research Center survey, women were asked if theypurchase books online, and responses included these: no, yes, no, no. Letting"yes" = 1 and letting "no" = 0, here are ten bootstrap samples for thoseresponses: \(\\{0,0,0,0\\},\\{1,0,1,0\\}\\{1,0,1,0\\},\\{0,0,0,0\\},\\{0,0,0,0\\},\\{0,1,0,0\\},\\{0,0,0,0\\},\\{0,0,0,0\\},\\{0,1,0,0\\},\\{1,1,0,0\\}.\) Using only the ten given bootstrap samples, construct a \(90 \%\) confidenceinterval estimate of the proportion of women who said that they purchase booksonline.
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Problem 34 Find the sample size required to... [FREE SOLUTION] (2024)
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