Get started for free
Log In Start studying!
Get started for free Log out
Chapter 7: Problem 34
Find the sample size required to estimate the population mean. Data Set 1 "Body Data" in Appendix B includes pulse rates of 147 randomlyselected adult females, and those pulse rates vary from a low of 36 bpm to ahigh of 104 bpm. Find the minimum sample size required to estimate the meanpulse rate of adult females. Assume that we want \(99 \%\) confidence that thesample mean is within 2 bpm of the population mean. a. Find the sample size using the range rule of thumb to estimate \(\sigma .\) b. Assume that \(\sigma=12.5\) bpm, based on the value of \(s=12.5\) bpm for thesample of 147 female pulse rates. c. Compare the results from parts (a) and (b). Which result is likely to bebetter?
Short Answer
Expert verified
Sample sizes are 479 (range rule) and 260 (\( \sigma = 12.5 \)). The latter is probably better.
Step by step solution
01
Determine the Required Formula
The formula for calculating the sample size required to estimate the population mean with a given level of confidence and margin of error is \[ n = \left( \frac{Z_{\frac{\alpha}{2}} \cdot \sigma}{E} \right)^2 \] where \( Z_{\frac{\alpha}{2}} \) represents the critical value from the standard normal distribution, \( \sigma \) is the population standard deviation, and \( E \) is the margin of error.
02
Identify Given Values and Compute Critical Value for 99% Confidence
Given: Confidence level, \( 99\% \), leads to \( \alpha = 0.01 \), thus \( \frac{\alpha}{2} = 0.005 \).From the Z-table, the critical value \( Z_{0.005} \) is 2.576.The margin of error \( E \) is 2 bpm.For part (a): Use the range rule of thumb to estimate \( \sigma \) as \( \frac{\text{Range}}{4} = \frac{104 - 36}{4} = 17 \). For part (b): Given \( \sigma = 12.5 \) bpm.
03
Calculate Sample Size Using the Estimated \( \sigma \)
Using the formula: \[ n = \left( \frac{2.576 \cdot 17}{2} \right)^2 = \left( 21.892 \right)^2 \approx 479 \] Therefore, the sample size required using the estimated \( \sigma \) is 479.
04
Calculate Sample Size Using the Given \( \sigma = 12.5 \)
Using the same formula: \[ n = \left( \frac{2.576 \cdot 12.5}{2} \right)^2 = \left( 16.1 \right)^2 \approx 260 \] Therefore, the sample size required using \( \sigma = 12.5 \) is 260.
05
Compare the Results
The sample sizes calculated are 479 (using the range rule of thumb) and 260 (using \( \sigma = 12.5 \) bpm). Part (b) uses an actual standard deviation from the data, so is likely a better estimate and requires a smaller sample size.
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
population mean
The population mean is the average value of a characteristic in a whole population. For example, in our exercise, we want to estimate the mean pulse rate of all adult females. This mean is often denoted by the Greek letter \( \mu \), and it represents the central value around which all individual measurements tend to cluster.
To calculate this population mean exactly, we would need to measure the pulse rate of every single adult female, which is obviously impractical. Instead, we take a sample (a subset of the population) and use the sample mean to estimate the population mean. The larger and more representative the sample, the more accurate our estimate of \( \mu \) will be.
In many real-world applications, such as our body data example, we rely on statistical methods like confidence intervals and the central limit theorem to make educated guesses about the population mean based on our sample data.
confidence interval
A confidence interval provides a range of values within which we can be certain the population mean lies, to a specified level of confidence. In our exercise, we are looking for a 99% confidence interval. This means that we are 99% sure that the true mean pulse rate falls within our calculated range.
The formula for a confidence interval around the population mean is given by: \[ \mu = \bar{x} \pm Z_{\frac{\alpha}{2}} \frac{\sigma}{\sqrt{n}} \] where \( \bar{x} \) is the sample mean, \( Z_{\frac{\alpha}{2}} \) is the z-value corresponding to our desired level of confidence, \( \sigma \) is the population standard deviation, and \( n \) is the sample size.
For a 99% confidence level, the critical z-value (\( Z_{\frac{\alpha}{2}} \)) is 2.576. This z-value provides the number of standard deviations we would expect the interval to cover. By calculating the margin of error \( E \) and applying it to our sample mean, we produce the confidence interval for the population mean.
standard deviation
The standard deviation (\( \sigma \) or s for a sample) is a measure of how spread out the values in a data set are. It shows the average distance of each data point from the mean of the data set. In the context of our pulse rate data, the standard deviation gives us an idea of how much the pulse rates of different individuals vary from the average pulse rate.
To find the sample size required to estimate the population mean, we need an estimate of the standard deviation. In our exercise, we use two methods to get this estimate:
- The range rule of thumb, which approximates standard deviation as one-fourth of the range of the data
- An actual standard deviation measured directly from the data (12.5 bpm in this case)
The formula for calculating standard deviation (\( s \)) for a sample is \[ s = \sqrt{ \frac{ \sum (x_i - \bar{x})^2 }{ n - 1 } } \] where \( x_i \) represents each value in the sample, \( \bar{x} \) is the sample mean, and \( n \) is the sample size.
Knowing the standard deviation is crucial because it affects the width of our confidence intervals and the required sample size. A smaller standard deviation generally means a smaller required sample size, as seen when comparing the results of parts (a) and (b) in our exercise.
One App. One Place for Learning.
All the tools & learning materials you need for study success - in one app.
Get started for free
Most popular questions from this chapter
Recommended explanations on Math Textbooks
Discrete Mathematics
Read ExplanationGeometry
Read ExplanationLogic and Functions
Read ExplanationDecision Maths
Read ExplanationApplied Mathematics
Read ExplanationStatistics
Read ExplanationWhat do you think about this solution?
We value your feedback to improve our textbook solutions.
Study anywhere. Anytime. Across all devices.
Sign-up for free
This website uses cookies to improve your experience. We'll assume you're ok with this, but you can opt-out if you wish. Accept
Privacy & Cookies Policy
Privacy Overview
This website uses cookies to improve your experience while you navigate through the website. Out of these, the cookies that are categorized as necessary are stored on your browser as they are essential for the working of basic functionalities of the website. We also use third-party cookies that help us analyze and understand how you use this website. These cookies will be stored in your browser only with your consent. You also have the option to opt-out of these cookies. But opting out of some of these cookies may affect your browsing experience.
Always Enabled
Necessary cookies are absolutely essential for the website to function properly. This category only includes cookies that ensures basic functionalities and security features of the website. These cookies do not store any personal information.
Any cookies that may not be particularly necessary for the website to function and is used specifically to collect user personal data via analytics, ads, other embedded contents are termed as non-necessary cookies. It is mandatory to procure user consent prior to running these cookies on your website.